Respuesta :
Answer:
[tex]n=\frac{121}{4}[/tex]
Step-by-step explanation:
Since we know that perfect square trinomial formula states that any trinomial of the form [tex]ax^{2} +bx+c[/tex] is said to a perfect square if it satisfies the condition [tex]b^{2} =4ac[/tex].
We are given an expression [tex]x^{2} ?11x ?n[/tex] and asked to find value of n for expression to be a perfect square trinomial .
Let us compare our expression with perfect square trinomial formula.
We can see that a=1, b=11 and c=n.
Let us find value of n by substituting our given values in [tex]b^{2} =4ac[/tex].
[tex]11^{2} =4*1*n[/tex]
[tex]121 =4n[/tex].
[tex]n=\frac{121}{4}[/tex]
Therefore, [tex]n=\frac{121}{4}[/tex] will make the expression [tex]x^{2} ?11x ?n[/tex] a perfect square trinomial.
