A person walks 5.0kilometers north, then 5.0 kilometers east. His displacement is closest to ? A. 10 kilometers northwest B. 7.1 kilometers northwest C. 10 kilometers northeast D. 7.1 kilometers northeast

Respuesta :

Use vector analysis and calculate resultant vector using Pythagoras theorem:
5^2 + 5^2 = 50
Square root of 50 = approx 7.1 km NE
Therefore the answer is D

Displacement is a vector quantity. That is, it has both magnitude and direction. The displacement of the person will be approximately 7.1 kilometers northeast.

The correct answer is option D

Given that a person walks 5.0 kilometers north, then 5.0 kilometers east.

Displacement is the distance covered in a specific direction.

The displacement of the person will be calculated by using a Pythagorean formula.

D = [tex]\sqrt{y^2 + x^2}[/tex]

D = [tex]\sqrt{5^2 + 5^2}[/tex]

D = [tex]\sqrt{25 + 25}[/tex]

D = [tex]\sqrt{50}[/tex]

D = 7.07 kilometers

The figure above is the magnitude of the displacement. The direction will be toward the northeast direction.

Therefore, the displacement of the person will be approximately 7.1 kilometers northeast.

The correct answer is option D

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