[tex]Solution,\mathrm{Inverse\:of}\:5x+4:\quad \frac{x-4}{5}[/tex]
[tex]Steps:[/tex]
[tex]y=5x+4[/tex]
[tex]\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y, x=5y+4[/tex]
[tex](\mathrm{Solve}\:x=5y+4\:\mathrm{for}\:y),(x=5y+4)[/tex]
[tex]\mathrm{Switch\:sides}, 5y+4=x[/tex]
[tex]\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}, 5y+4-4=x-4[/tex]
[tex]\mathrm{Simplify}, 5y=x-4[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}5, \frac{5y}{5}=\frac{x}{5}-\frac{4}{5}[/tex]
[tex]\mathrm{Simplify}, y=\frac{x-4}{5}[/tex]
[tex]\mathrm{The\:Correct\:Answer\:is\:\frac{x-4}{5}}[/tex]
[tex]\mathrm{Hope\:This\:Helps!!!}[/tex]
[tex]\mathrm{-Austint1414}[/tex]
