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a series circuit contains two devices one with a resistance of 10 ohms and one with a resistance of 4 ohms if the generator supplies a voteage of 42 v what is the magnitude of the current?

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Current(I) = Voltage/Resistance

                = 42/(10+ 4)

                = 42/14  

Current = 3 A      

Answer:

i = 3 A

Explanation:

When two or more resistances are connected in series then the total effective resistance is given as

[tex]R_{eq} = R_1 + R_2[/tex]

now we have

[tex]R_{eq} = 10\: ohm + 4\: ohm[/tex]

[tex]R_{eq} = 14\: ohm[/tex]

now from ohm's law we know that

[tex]V = i R[/tex]

here we know that

V = 42 volts

R = 14 ohm

now from above equation

[tex]42 = i \times 14[/tex]

[tex]i = 3 A[/tex]

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