[tex]g(x)=(x-3)^{2} +2[/tex] has the same shape as the parabola [tex]g(x)=x^{2}[/tex] but with vertex shifted to (3, 2).
The vertex of the parabola [tex](y-k)^{2} =4a(x-h)[/tex] is (h, k).
Equation of the given graph is [tex]g(x) = (x-3)^{2} +2[/tex]
Subtract 2 from both sides.
[tex]g(x)-2=(x-3)^{2}[/tex]
Hence, its vertex is at (3, 2).
Please find the attached graph.
