Answer:
the equation of the line that is parallel to y=14x-3 and goes through (1, 22) is y=14x+8
Step-by-step explanation:
y=14x-3
y-y1=m(x-x1) where m is the slope and (x1, y1) is the given point (1, 22)
y-22=14(x-1)
plug in m=14, x1= 1 and y1= 22
y-22=14x-(14)*(1) distribute 14
y-22=14x-14 multiply
y=14x-14+22 add 22 to both sides to isolate (leave alone) y
y+14x+8
Hope this helped! Have a good day. :)
