Answer: At t=0.015 hours when the car 0.6 miles from the check point.
Step-by-step explanation:
Since we have given that
Distance traveled by him towards a speed check point = 1.4 miles
Speed at which he is travelling = 52 miles per hour
Let the time taken by him be x
Since we have the equation
[tex]d=1.4-52t[/tex]
where d denotes distance
and t denotes time.
If we have given that the car 0.6 miles from the check point.
So, we put the value of d in place of it .
[tex]0.6=1.4-52t\\\\0.6-1.4=-52t\\\\-0.8=-52t\\\\0.8=52t\\\\\frac{0.8}{52}=t\\\\0.015=t[/tex]
So, at t=0.015 hours when the car 0.6 miles from the check point.