Answer-
The margin of error of the sample is 20.60
Solution-
We know that,
[tex]\mu=M\pm ME[/tex]
where:
[tex]\text{M = sample mean}\\\\\text{ME = margin of error}[/tex]
According to the question,
[tex]168.8=M+ME\ and\ 127.6=M-ME[/tex]
Subtraction equation 2 from equation 1,
[tex]\Rightarrow 168.8-127.6=2ME[/tex]
[tex]\Rightarrow 2ME=168.8-127.6=41.2[/tex]
[tex]\Rightarrow ME=\dfrac{41.2}{2}[/tex]
[tex]\Rightarrow ME=20.60[/tex]
Therefore, the margin of error of the sample is 20.60
