Respuesta :
Answer: The inequality is [tex]315-90x\geq 0[/tex]. The hose can be on for less that or equal to[tex]3\frac{1}{2}[/tex] hours.
Explanation:
The capacity of tank is 315 gallons.
Let the hose can on for time (in hours) t.
The hose is filling the fish tank at a rate of 15 gallons every 10 minutes.
10 min = 15 gallons
1 min = 1.5 gallons
Because we know that 1 hour = 60 min,
1 hour = 1.5(60) = 90
Therefore the tank is filling 90 gallon per hour.
The tank filled in t hours is 90t.
Since the capacity of tank is 315 gallons. So 90t is always less than 315.
[tex]90t\leq 315[/tex]
[tex]0\leq 315-90t[/tex]
It can be written as [tex]315-90x\geq 0[/tex].
Solve the inequality we get,
[tex]90t\leq 315[/tex]
[tex]t\leq 3\frac{1}{2}[/tex]
So the hose can be on for less that or equal to[tex]3\frac{1}{2}[/tex] hours.
Answer:
3 1/2 hours
Step-by-step explanation:
315 / 15 = 21
21 x 10 = 210
210 / 60 = 3.5
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