Respuesta :
ANSWER
Find out the what will be the ratio of Julia's frogs to Rimma's frogs.
To proof
let us assume that the amount of Rimma's frogs = x
[tex]Julia's\ frogs\ are\ \frac{2}{5}\ of\ the\ amount\ of\ Rimma's\ frogs.[/tex]
than the
Julia's frogs becomes
[tex]=\frac{2x}{5}[/tex]
As given
[tex]If\ Rimma\ gives\ \frac{1}{2}\ of\ her\ frogs\ to\ Julia,[/tex]
than the
Rimma's frogs becomes
[tex]=x- \frac{x}{2} \\= \frac{x}{2}[/tex]
Julia's frogs becomes
[tex]= \frac{2x}{5}+ \frac{1x}{2} \\ =\frac{9x}{10}[/tex]
Than the ratio of Julia's frogs to Rimma's frogs
[tex]\frac{Julia's\ frogs}{ Rimma's frogs} = \frac{9x\times2}{10\times x}[/tex]
thus
[tex]=\frac{9}{5}[/tex]
Hence proved
Answer:
9:5
Step-by-step explanation:
Rimma = x
Julia = 2/5 x
Rimma gives away 1/2 of her frogs.
Now Rimma has 1/2x and Julia has 2/5x + 1/2x=4/10x +5/10x =9/10x
Ratios are fractions so put Julia's on top of Rimma's and simplify.
(9/10 x) / (1/2x)
The x's will cancel. Invert the second fraction and multiply.
(9/10)*(2/1) = 18/10= 9/5
Ratio of Julia's frogs to Rimma's frogs is 9:5.
