Answer:
D. 21.6 m/s
Explanation:
This problem is a projectile motion problem, where we know that the ball reaches a horizontal distance of x=44 m in a time of t=2.9 s. We also know that the ball was kicked with an angle of [tex]\theta=45^{\circ}[/tex].
We are only interested in the horizontal motion of the ball, which is a uniform motion with constant speed [tex]v_0 cos \theta[/tex], where [tex]v_0[/tex] is the initial speed of the ball. The horizontal velocity is simply equal to the ratio between the horizontal distance and the time:
[tex]v_0 cos \theta=\frac{x}{t}[/tex]
Re-arranging the equation, we find
[tex]v_0 = \frac{x}{t cos \theta}=\frac{44 m}{(2.9 s)( cos 45^{\circ})}=21.5 m/s[/tex]
So, the best answer is
D. 21.6 m/s