A yogurt shop allows its customers to add, for no charge, 3 toppings to any yogurt purchased. If the store has 15 possible toppings, how many different 3-topping combinations can a customers choose?

Respuesta :

Question says that a yogurt shop allows its customers to add, for no charge, 3 toppings to any yogurt purchased. Also the store has 15 possible toppings.

Now we need to find about how many different 3-topping combinations can a customers choose.

To find that we just need to apply combination formula

[tex]C(n,r)=\frac{n!}{r!(n-r)!}[/tex]

which is used to select r items out of n items

we have to find combination of 15 toppings into 3 toppings so we calculate C(15,3) using above formula

[tex]C(15,3)=\frac{15!}{3!(15-3)!}[/tex]

[tex]C(15,3)=\frac{15!}{3!*12!}[/tex]

[tex]C(15,3)=\frac{15*14*13*12!}{3!*12!}[/tex]

[tex]C(15,3)=\frac{15*14*13}{3!}[/tex]

[tex]C(15,3)=\frac{2730}{6}[/tex]

[tex]C(15,3)=455[/tex]

Hence final answer is 455.

Answer:

only 455

Step-by-step explanation:

i have a ? how do you know when its C(n,r) and not P(n,r)