How would the fraction 1/3+square root of 2 be rewritten if its denominator is rationalized using difference of squares? A. 3-square root of 2 B. 3-square root of 2/5 C. 3-square root of 2/7 D. - 3+square root of 2/7

Respuesta :

C

given 1 /( 3 + √2 )

then rationalise the denominator by multiplying the numerator/ denominator by the conjugate of the denominator

the conjugate of 3 + √2 is 3 - √2

1 / (3 + √2 ) × (3 - √2 ) / (3 - √2 )

= (3 - √2 ) /( 9 - 2 ) = (3 - √2 ) / 7

The fraction [tex]\frac{1}{3+\sqrt{2}}[/tex] can be written as [tex]\frac{3-\sqrt 2}{7}[/tex]. Option C is correct.

What is a fraction simplification?

Fraction simplification is a method of fraction reduction that entails making a fraction as simple as possible.

This is accomplished by dividing the numerator and denominator by the biggest integer that divides both integers exactly.

Given fraction;

[tex]\frac{1}{3+\sqrt{2}}[/tex]

Multiplying the numerator and denominator by the conjugate of the denominator will rationalize the denominator;

The conjugate of the denominator (3 + √2) is 3 - √2;

Apply the rationalization of fraction;

[tex]\frac{1}{3+\sqrt{2}} \\\ \frac{1}{3+\sqrt{2}} \times \frac{3-\sqrt2}{3-\sqrt 2} \\\\ \frac{3-\sqrt 2}{9-2} \\\\\ \frac{3-\sqrt 2}{7}[/tex]

Hence option C is correct.

To learn more about fraction simplification, refer to https://brainly.com/question/11479469.

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