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find the factorization of the polynomial below. 100x^2-20x+1
A. (10x+1)^2
B. (10-1)^2
C. (50x+1)^2
D. (50x-1)^2

Respuesta :

ANSWER

The factorization of   [tex]100x^2-20x+1[/tex]

 is [tex](10x-1)^2[/tex].


EXPLANATION

We want to factor [tex]100x^2-20x+1[/tex]


Comparing this to [tex]ax^2+bx+c[/tex]


[tex]a=100,b=-20,c=1[/tex]


[tex]ac=100[/tex]

We look for factors of 100  that add up to [tex]-20[/tex].


These factors are [tex]-10,-10[/tex]


We now split the middle term to obtain;


[tex]100x^2-10x-10x+1[/tex]

We factor to obtain;

[tex]10x(10x-1)-1(10x-1)[/tex]


This simplifies to  [tex](10x-1)(10x-1)=(10x-1)^2[/tex]


Answer:B

Step-by-step explanation:

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