Respuesta :
ANSWER
[tex]y=12[/tex]
EXPLANATION
One way is to make x the subject in one equation and substitute into the other.
[tex]2x+2=y[/tex]
[tex]\Rightarrow 2x=y-2[/tex]
[tex]\Rightarrow x=\frac{y}{2}-1--(1)[/tex]
The second equation is
[tex]2y=5x-1--(2)[/tex]
Let us put equation 1 in 2
[tex]\Rightarrow 2y=5(\frac{y}{2}-1)-1[/tex]
[tex]\Rightarrow 2y=\frac{5y}{2}-5-1[/tex]
[tex]\Rightarrow 2y=\frac{5y}{2}-6[/tex]
Multiplying through by 2 gives;
[tex]\Rightarrow 4y=5y-12[/tex]
[tex]\Rightarrow 4y-5y=-12[/tex]
[tex]\Rightarrow -y=-12[/tex]
[tex]\Rightarrow y=12[/tex]
D
given the 2 equations
2x + 2 = y → (1)
2y = 5x - 1 → (2)
Substitute y = 2x + 2 into (2)
2(2x + 2) = 5x - 1
4x + 4 = 5x - 1 ( subtract 5x from both sides )
- x + 4 = = - 1 ( subtract 4 from both sides )
- x = - 5 ( multiply through by - 1 )
x = 5
substitute x = 5 into (1)
y = (2 × 5 ) + 2 = 10 + 2 = 12 → D