the price of a train ticket consists of an initial fee plus a constant fee per stop. the table compares the number of stops and the price of a ticket(in dollars) plz help

the price of a train ticket consists of an initial fee plus a constant fee per stop the table compares the number of stops and the price of a ticketin dollars p class=

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Answer:

is it 1.50? I got it wrong tho

We can express the question using an algebraic expression. This algebraic expression would be having two variables, x and y.

We are told in the question that:

The price of a train ticket consists of an initial fee plus a constant fee per stop.

Where:

x = Initial fee

y = Constant fee per stop

For 3 stops, our algebraic expression is given as:

x + 3y = 6.50...........Equation 1

To find the fee per stop, we compare with the algebraic expression for 7 stops

For 7 stops, our algebraic expression is given as:

x + 7y = 12.50...............Equation 2

We solve for y(constant fee per stop) using the Elimination Method.

We eliminate x by subtracting Equation 1 from Equation 2

x + 3y = 6.50...........Equation 1

x + 7y = 12.50..........Equation 2

7y - 3y = 12.50 - 6.50

4y = 6.00

Divide both sides by the coefficient of y = 4

4y/4 = 6.00/4

y = 1.50.

Therefore, the fee per stop is $1.50

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