When car is at the top of the hill its whole energy is stored in the form of gravitational potential energy
[tex]U = mgh[/tex]
so when height of the car becomes half then its potential energy is given as
[tex]U_f = \frac{mgh}{2}[/tex]
so final potential energy when car falls down by half of the height will become half of the initial potential energy
So it is U = 50 MJ after falling down
Now by energy conservation we can say that final potential energy + final Kinetic energy must be equal to the initial potential energy of the car
So here at half of the height kinetic energy of car = 100 - 50 = 50 MJ
so we can say at this point magnitude of potential energy and kinetic energy will be same
A. the same as the potential energy at that point.
