Given the function [tex]f(x)=\dfrac{1}{3}(3x+9)-6x.[/tex]
1) Find x-intercept:
when y=0, then
[tex]\dfrac{1}{3}(3x+9)-6x=0,\\ \\x+3-6x=0,\\ \\-5x=-3,\\ \\x=\dfrac{3}{5} .[/tex]
Point [tex]\left(\dfrac{3}{5},0\right)[/tex] is x-intercept.
2) Find y-intercept:
when x=0, then
[tex]y=\dfrac{1}{3}(3\cdot 0+9)-6\cdot 0=\dfrac{1}{3}\cdot 9=3.[/tex]
Point (0,3) is y-intercept.
Answer: correct option is B
