Answer: Option 'C' is correct.
Step-by-step explanation:
Since we have given that
Dimensions of I st box as shown in the figure below:
Length = 5 units
Width = 2 units
So, Area of Ist box will be given as
[tex]Length\times Breadth=5\times 2=10\ sq.\ units[/tex]
Dimensions of II nd box as shown in the figure below:
Length = 2 units
Width = 1 unit
So, Area of II nd box will be given as
[tex]Length\times Breadth=2\times 1=2\ sq.\ units[/tex]
Similarly,
Dimensions of III rd box as shown in the figure below:
Length = 3 units
Width = 2 units
So, Area of III rd box will be given as
[tex]Length\times Breadth=3\times 2=6\ sq.\ units[/tex]
Total area of the polygon will be
[tex]10+2+6=18\ sq.\ units[/tex]
Hence, Option 'C' is correct.
