How far is Abraham's house from Scarlet's house? Please provide an answer and show or explain your calculations. Abraham's house is 3 1/6 blocks to the South Scarlet's house is 4 1/3 blocks to the North

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Answer:

Abraham's house is [tex]7\frac{1}{2}[/tex] blocks far from Scarlet's house.

Step-by-step explanation:

Abraham's house is [tex]3\frac{1}{6}[/tex] blocks to the South and Scarlet's house is [tex]4\frac{1}{3}[/tex] blocks to the North.

As the two houses are in opposite direction, so for finding the total distance between two houses, we need to add the two distances.

[tex]3\frac{1}{6}+4 \frac{1}{3} \\ \\ =\frac{19}{6}+ \frac{13}{3} \\ \\ =\frac{19}{6}+ \frac{13*2}{3*2} \\ \\ =\frac{19}{6}+ \frac{26}{6}= \frac{19+26}{6}= \frac{45}{6}= \frac{15}{2}=7 \frac{1}{2}[/tex]

So, Abraham's house is [tex]7\frac{1}{2}[/tex] blocks far from Scarlet's house.