can someone plz help me!!! 5-7?!

Answer:
#5: d=22, #6: [tex]m=4\frac1{10}[/tex], #7: [tex]2\frac3{11}=z[/tex]
Step-by-step explanation:
#5:
[tex]2\cdot (4\cdot5-3^2)=2\cdot (4\cdot5-3\cdot3)=2\cdot (20-9)=2\cdot11=22[/tex]
#6:
[tex]5\frac25-1\frac3{10}=5\frac4{10}-1\frac3{10}=4\frac1{10}[/tex]
#7:
[tex]\frac{40-15}{5+6}=\frac{25}{11}=2\frac3{11}[/tex]
Answer:
5. [tex]d = 22[/tex]
6. [tex]m = 4\frac{1}{10}[/tex]
7. [tex]z = 2\frac{3}{11}[/tex]
Step-by-step explanation:
5. [tex]d = 2 (4[/tex] · [tex]5 - 3^2)[/tex]
Solving the terms inside the brackets first:
[tex]d = 2 (20 - 9)[/tex]
[tex]d = 2 (11)[/tex]
[tex]d = 22[/tex]
6. [tex]m = 5\frac{2}{5} - 1\frac{3}{10}[/tex]
[tex]m = \frac{27}{5} - \frac{13}{10}[/tex]
By taking LCM:
[tex]m = \frac{54 - 13}{10}[/tex]
[tex]m = \frac{41}{10}[/tex]
[tex]m = 4\frac{1}{10}[/tex]
7. [tex]\frac{40-15}{5+6} = z[/tex]
Taking the denominator to the other side of the equation and multiplying it there:
[tex]40 - 15 = z (5 + 6)[/tex]
[tex]25 = 5z + 6z[/tex]
[tex]11z = 25[/tex]
[tex]z = \frac{25}{11}[/tex]
[tex]z = 2\frac{3}{11}[/tex]