please help i will award brainliest!!!! AB , CD and EF are straight lines intersecting at point O. Find m∠AOC, m∠BOF, m∠COF, m∠COE.

angle EOD
180 = AOE + EOD + DOB
180 = 15 + EOD + 37
180 = 52+EOD
subtract 52 from each side
EDO = 128
COF
COF = 128 vertical angles (EDO)
AOC
AOC =37 vertical angles (DOB)
BOF
BOF = 15 vertical angles (EOA)
COE
COE = COA+AOE
=37+15
= 52
The measure of m∠AOC, m∠BOF, m∠COF, and m∠COE are 37, 15, 128, and 52degrees respectively.
The point where two lines meet is known as an angle
From the diagram given:
m<AOE + m<EOD + m<DOB = 180
15 + m<EOD + 37 = 180
m<EOD = 180 - 52
m<EOD = 128 degrees
From the diagram m<DOB = m<AOC = 37 degrees (vertical angles)
m∠BOF = m∠AOE = 15 degreed (vertical angles)
m∠COF = m∠EOD = 128 degrees (vertical angles)
m∠COE = m∠COA + m∠AOE
m∠COE = 15 + 37
m∠COE = 52 degrees
Hence the measure of m∠AOC, m∠BOF, m∠COF, and m∠COE are 37, 15, 128, and 52degrees respectively.
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