here as it is given that x component of the vector is positive while y component of the vector is negative so we can say the vector must inclined in Fourth quadrant.
So angle must be more than 270 degree and less than 360 degree
Now in order to find the value we can say that
[tex]tan\theta = \frac{opposite\: side}{adjacent\: side}[/tex]
[tex]tan\theta = \frac{8.6}{6.1}[/tex]
[tex]\theta = tan^{-1}1.41[/tex]
[tex]\theta = 54.65^0[/tex]
so it is inclined at above angle with X axis in fourth quadrant
Now if angle is to be measured counterclockwise then its magnitude will be
[tex]\theta = 360 - 54.65 = 305.3^0[/tex]
so the correct answer will be 305 degree
