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Janelle is at the movie theater and has $20 to spend.
She spends $8 on a ticket and wants to buy some snacks. Each snack costs $4.99.
How many snacks, x, can Janelle buy?

Inequality that represents this situation:
20≥8+4.99x

Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution.

Respuesta :

Answer:

you minus 8 from 20 which will = to 12. Then you divide 12 by 4.99 and it equals to like 2.4 but you can't buy a .4 of a candy bar so have to round it down to 2

Step-by-step explanation:

Answer:

[tex]x\leq 2.40[/tex]

Step-by-step explanation:

Cost of ticket = $8

Cost of 1 snack = $4.99

Let x be the number of snacks

Cost of x snacks = 4.99x

So, total cost = 8+4.99x

Now we are given that she has $20

So, inequality becomes: [tex]8+4.99x\leq 20[/tex]

[tex]4.99x\leq 20-8[/tex]

[tex]4.99x\leq 12[/tex]

[tex]x\leq \frac{12}{4.99}[/tex]

[tex]x\leq 2.40[/tex]

So, Janie cannot buy more than 2 snacks.

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