Hello there!
I’m assuming you mean y=(5/3)x+10 correct me if there’s supposed to be a 2 in there.
First of all, to get a slope perpendicular to 5/3, flip the fraction and multiply it by negative 1.
-3/5
So now we have the line:
y=(-3/5)x+b
Now plug the point (10,-3) into the equation.
-3=(-3/5)10+b
-3=-30/5+b
-3=-6+b
3=b
Now plug the 3 in for b into the equation.
y=(-3/5)x+3
I hope this helps!
Best wishes :)
-HuronGirl
