For N2(g)+3h2(g) ←→ 2nh3(g) The equilibrium system described by this equation has= 3 reactant molecule(s) and= 2 product gas molecule(s).
The given equilibrium system has the number of reactant molecules are 4, and the number of product molecules are 2.
Equilibrium has been the condition that has been marked with the presence of equal number of product and reactant.
The given reaction has been:
[tex]\rm N_2\;+\;3\;H_2\;\leftrightharpoons\;2\;NH_3[/tex]
The number of atoms of each molecule on the product and the reactant side has been equal. The number of molecules has been the repeating unit for reactant and product.
The number of molecules on the reactant side has been the sum of hydrogen and nitrogen molecules. The number of hydrogen has been 3, while the number of nitrogen has been 1.
The total number of reactant molecule has been 4.
The number of product molecules, are 2 molecules of ammonia.
Thus, in the given equilibrium system, the number of reactant molecules are 4, and the number of product molecules are 2.
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