Respuesta :
Answer:
Step-by-step explanation:
First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items
F(x) = x^3-3x^2+0x+0
We have to divide this by x-2
Leading terms in the dividend and divisor are
x^3 and x
Hence quotient I term would be x^3/x=x^2
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
Multiply x-2 by x square and write below the term and subtract
We get
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
---------------
-x^2+0x
Again take the leading terms and find quotient is –x
x-2) x^3-3x^2+0x+0(x^2-x
x^3-2x^2
---------------
-x^2+0x
-x^2-2x
Subtract to get 2x +0 as remainder.
x-2) x^3-3x^2+0x+0(x^2-x-2
x^3-2x^2
---------------
-x^2+0x
-x^2+2x
-------------
-2x-0
-2x+4
------------------
-4
Thus remainder is -4 and quotient is x^2-x-2
Using long division, the quotient and remainder obtained by dividing x³ - 3x² by x - 2 are (x² - x + 2) and 4 respectively.
- Dividend = x³ - 3x²
- Divisor = x - 2
____| x² - x + 2 ___________Quotient
____________
x - 2 | x³ - 3x²
____| x³ - 2x²
-___ | ___-x²
________-x² - 2x
-__________+2x
___________2x - 4
-______________4 ________ Remainder
Therefore, the quotient and the remainder values are (x² - x + 2) and 4 respectively.
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