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The length of a rectangle is 3 more inches than the width. Find the length and width of the rectangle is the perimeter of the rectangle is 54 inches.

#7 Write an equation that represents the situation. Explain any variable used.




#8 Solve the equation. Show your work. State your solution as a complete sentence

Respuesta :

Part A:

Let the width of the rectangle be = x inches

As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches

Perimeter is given as = 54 inches

Perimeter = [tex]2(l+b)[/tex]

Equation becomes:

[tex]2(x+3+x)[/tex]=54

[tex]2(2x+3)=54[/tex]

Part B:

Solving the equation we get

[tex]4x+6=54[/tex]

[tex]4x=54-6[/tex]

[tex]4x=48[/tex]

[tex]x=12[/tex]

Hence, the width of the rectangle is 12 inches

Length = x+3 = 12+3 = 15 inches

Hence, length of the rectangle is 15 inches.


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