Answer:
Real power,P is 10.286 Watts
Step-by-step explanation:
We are given that in a parallel circuit, [tex]E_{T}=240V[/tex],R=5.6kΩ and [tex]X_{L}[/tex]=3.6kΩ
We are asked to find P which means real power, that is power due to resistance.
Let us find current through resistor first.
That is [tex]I_{R}=\frac{E_{T}}{R}=\frac{240}{5.6}=\frac{300}{7}=42.86[/tex]milli Amps=0.04286 A
Hence [tex]P=E_{T}I_{R}[/tex]
=240X0.04286=10.286 Watts
