Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott traveled 10. Calculate each person's speed and tell who rode faster. (s=d/t)

A)Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

B)Scott had the faster speed since he rode at 10 km/h and Jill was riding at 5 km/h

C)Jill was traveling faster. She was riding at a speed of 10 km/h while Scott was traveling at 20 km/h.

D)Both Jill and Scott were traveling at the same speed since they both rode their bikes for 30 minutes.

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aristocles aristocles · Answer 1 · 2018-11-04T05:12:48+01:00

time for which Jill and Scott both traveled is 30 min

as we know that

1 hour = 60 min

now we will convert the time of travel from minutes to hour

[tex]t = \frac{30 min}{60 min}* 1 hour[/tex]

[tex]t = 0.5 hour[/tex]

now we will have to find the speed of both

For speed we know the formula

[tex]speed = \frac{distance}{time}[/tex]

speed of Jill as he cover 5 km in 30 min

[tex]v_1 = \frac{5}{0.5} = 10 km/h[/tex]

speed of Scott as he cover 10 km in 30 min

[tex]v_2 = \frac{10}{0.5}= 20 km/h[/tex]

so correct answer is

A)Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

wiseowl2018 wiseowl2018 · Answer 2 · 2019-02-25T23:55:57+01:00

Speed of Jill is greater than Scott

As we know that

Speed = Distance / Time

So speed of Jill is = 5 / 0.5 since 30 minutes = 0.5 hours

Speed of Jill = 10 km/hour

And

speed of Scott is = 10 / 0.5

Speed of Scott = 20 km/min

Here we can see that speed of Scott is greater than Jill

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