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retta has 40 raffle tickets to sell. She is required to sell at least 15 tickets. She sells the raffle tickets for $10 each. The amount of money Gretta makes from selling x raffle tickets is represented by a function. f(x)=10x What is the practical range of the function?

Respuesta :

it should be 400 considering raffle=xĂ—10=400

Answer:

[150,400]

Step-by-step explanation:

Retta has 40 raffle tickets to sell and she has to sell at least 15 tickets. So, the interval that represents this situation is [tex][15,40][/tex], because the minimum allowed is 15 tickets, and the maximum possible is 40 tickets.

We know by given that the function that models this situation is

[tex]f(x)=10x[/tex]

To find the valid range, we just need to find the values assigned to [tex]x=15[/tex] and [tex]x=40[/tex].

[tex]f(x)=10x\\f(15)=10(15)=150[/tex]

[tex]f(x)10x\\f(40)=10(40)=400[/tex]

Therefore, the practical range of the function is [150,400]

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