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Consider the function f(x)=3x-1 (over)x+4 (a) At which value of x will the function not have a solution? Explain your answer. (b) If g(x) is a vertical shift of 4 units of f(ax), write the function of g(ax). How does the graph 3. Consider the function f(x) of g(x) compare to the graph of f(x)? Explain the function you wrote. (e) What is the value of x when g(x) 8? Show your work. PLEASE HELP ITS DUE!!! I’ll make you brainliest

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remotecontrolbrain

Function [tex]f(x)=\frac{3x-1}{x+4}[/tex]

(a) the function is undefined at x=-4. At x=-4 the denominator becomes 0 and the function has a singularity (-> is no longer a function there)

(b) I am assuming the vertical shift is 4 units UP (your question does not say):

[tex]g(x)=f(x)+4=\frac{3x-1}{x+4}+4=\frac{(3x-1)+4x+16}{x+4}=\frac{7x+15}{x+4}[/tex]

(c) the graph of g(x) compared to f(x) is shifted upwards by 4 units, maintain shapes of the curves.

(d) missing?

(e)

[tex]g(x) = \frac{7x+15}{x+4} = 8 \\7x+15=8x+32\\\rightarrow x = -17[/tex]


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