contestada

Morgan is making two cookie recipes. Recipe A calls for one-third less than twice the number of cups of sugar that Recipe B calls for. If she needs four and one-sixths cups of sugar in all, how many cups will she need for Recipe A?

Respuesta :

Answer:

1 & 1/6

Step-by-step explanation:

You only need half the amount of sugar so you multiply by 1/2. so 2 cups and 1/3.

2\1 X 1/2 = 2/2=1 cup

1/3X1/2=1/6

1+1/6= 1 & 1/6

This question can be solved by the Operation of fractions such as: Addition, Subtraction, Multiplication, and Division.

The number of cups of sugar she will need for Recipe A is

Let the number of cups of sugar for:

Recipe A = a

Recipe B = b

Recipe A calls for one-third less than twice the number of cups of sugar that Recipe B calls for.

This statement can be represented mathematically as:

a = 2b - [tex]\frac{1}{3}[/tex]  

We are also told that she needs [tex]4\frac{1}{6}[/tex] cups of sugar in all.

This means: a + b = [tex]4\frac{1}{6}[/tex]cups of sugar

Substituting 2b - [tex]\frac{1}{3}[/tex]  for a

We have:

2b - [tex]\frac{1}{3}[/tex] = [tex]4\frac{1}{6}[/tex]

Add [tex]\frac{1}{3}[/tex]  to both sides

2b - [tex]\frac{1}{3}[/tex]  + [tex]\frac{1}{3}[/tex]  = [tex]4\frac{1}{6}[/tex]  +[tex]\frac{1}{3}[/tex]

2b = [tex]4\frac{1}{2}[/tex]

Divide both sides by 2

2b/2 =  [tex]4\frac{1}{2}[/tex] / 2

b =  [tex]\frac{9}{2}[/tex] / 2

b = [tex]\frac{9}{2}[/tex]  x 2/1

b = 9 cups

Therefore, Recipe B needed 9 cups of sugar.

Solving for Recipe A

a = 2b - 1/3

a = 2 x 9 - 1/3

a = 18 - 1/3

a = [tex]17\frac{2}{3}[/tex] cups of sugar

Therefore, Recipe A needs [tex]17\frac{2}{3}[/tex]cups of sugar

To learn more, visit the link below:

https://brainly.com/question/17149247

Otras preguntas