ANSWER
The point [tex](\frac{2}{9},-7)[/tex] lies on the straight line [tex]y+7=-3(x-\frac{2}{9})[/tex]
EXPLANATION
The given line is [tex]y+7=-3(x-\frac{2}{9})[/tex]. It can be observed that the given straight line is in the point-slope form.
We can rewrite the equation in the point-slope form to obtain,
[tex]y--7=-3(x-\frac{2}{9})[/tex].
When we compare this to the general point-slope form, which given by the formula;
[tex]y-y_1=m(x-x_1)[/tex],
We can observe that,
[tex]x_1=\frac{2}{9}[/tex] and [tex]y_1=-7[/tex].
Hence the point, [tex](x_1,y_1)=(\frac{2}{9},-7)[/tex] lies on [tex]y+7=-3(x-\frac{2}{9})[/tex]
