If $4200 is invested in savings account for which interest is compounded semianually, and if the $4200 turns into $4900 in 4 years , what is the interest rate of the savings account

Respuesta :

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

A=final amount

P=initial amount invested

r=rate in decimal form

n=number of times compounded per year

t=time in years


given

A=4900

P=4200

r=r (we are solving for this)

n=semianually=2 times per year

t=4

find r


[tex]4900=4200(1+\frac{r}{2})^{2*4}[/tex]

[tex]4900=4200(1+\frac{r}{2})^8[/tex]

divide both sides by 4200

[tex]\frac{4900}{4200}=(1+\frac{r}{2})^8[/tex]

take 8th root of both sides

[tex]\sqrt[8]{\frac{49}{42}}=1+\frac{r}{2}[/tex]

minus 1

[tex]-1+\sqrt[8]{\frac{49}{42}}=\frac{r}{2}[/tex]

multiply both sides by 2

[tex]-2+2\sqrt[8]{\frac{49}{42}}=r[/tex]

r=0.038911

r=3.891% so about 3.89%