Respuesta :
The reaction is:
Cr₃⁺ +3 C₁₀H₈N₂ → [Cr(C₁₀H₈N₂)₃]³⁺
2,2\'-bipyridine is bidentate ligand and neutral. It exhibits two N terminal, thus, it functions as bidentate ligand.
Therefore, three 2,2\'-bipyridine ligand fulfills the six coordination number of Cr₃⁺.
The formula for the complex is [Cr(C₁₀H₈N₂)₃]³⁺
Answer: The formula of the complex will be [tex][Cr(C_{10}H_8N_2)_3]^{3+}\text{ or }[Cr(bpy)_3]^{3+}[/tex]
Explanation:
Coordination number in a complex is defined as the number of ligands that are attached to the central metal atom.
- If the ligand is unidentate, it will occupy 1 place around the central metal atom.
- If the ligand is bidentate, it will occupy 2 places around the central metal atom.
- If the ligand is tridentate, it will occupy 3 places around the central metal atom.
We are given:
A metal ion having formula [tex]Cr^{3+}[/tex] and ligand attached to it is 2,2'-bipyridine (shortly named as 'bpy')
Coordination number of the complex is 6
We know that, 'bpy' is a bidentate ligand and does not carry any charge on it
Hence, the formula of the complex will be [tex][Cr(C_{10}H_8N_2)_3]^{3+}\text{ or }[Cr(bpy)_3]^{3+}[/tex]
