A
since the 3 is outside the radical then [tex]\sqrt{9}[/tex] = 3, hence
x = 9
B
using the law of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] = [tex]\sqrt{ab}[/tex]
we can separate the factors as
[tex]\sqrt{24}[/tex] × √[tex]x^{10}[/tex] × √[tex]y^{5}[/tex]
= 2[tex]\sqrt{6}[/tex] [tex]x^{5}[/tex][tex]y^{5/2}[/tex]
C
[tex]\sqrt{121}[/tex] + [tex]\sqrt{50}[/tex] = 11 + 5[tex]\sqrt{2}[/tex]
D
[tex]\sqrt{20}[/tex] × [tex]\sqrt{63}[/tex]
= 2[tex]\sqrt{5}[/tex] × 3[tex]\sqrt{7}[/tex]
= 6[tex]\sqrt{35}[/tex]
