Can someone help with this

[tex]T(l) = T = 2\pi \sqrt{\frac{l}{32.2} \\[/tex]
[tex]T^2 = 4\pi^2 \frac{l}{32.2}\\32.2T^2 = 4\pi^2 l\\\frac{32.2}{4\pi^2}T^2 = l\\l (T)= \frac{8.05}{\pi^4} T^2[/tex]
Then if T = 3s
[tex]l(3) = \frac{8.05}{4\pi^2}(3^2)ft[/tex]