If 21 mL of gas is subjected to a temperature change from 10.0°C to 120°C and a pressure change from 1.0 atm to 15 atm, the new volume is: (Be sure to use the correct number of significant figures.) 1.9 mL 1.0 mL 0.53 mL 440 mL

Respuesta :

 The  new volume is  1.9  ml


calculation

The new   volume  is  calculated using the   combined gas  equation

that is  P1V1/T1 = P2V2/T2  where

P1= 1.0 atm

V1= 21   ml

T1 = 10.0 c  into kelvin = 10 + 273 = 283 k

P2 = 15 atm

V2=? Ml

T2 = 120 c  into kelvin = 120 +273 = 393 K


make V2  the subject of the   formula by  multiplying  both side  by T2/P2

V2=T2P1v1 / P2T1

V2=[(393 k  x 1.0 atm  x 21  ml) / (15 atm x 283 K)]  = 1.9  Ml


Answer:

1.9  ml

Explanation:

please leave a thanks! <3