Respuesta :
Answer:
[tex]p=10\sqrt[3]{54}x^2[/tex]
Step-by-step explanation:
We are given parallelogram
Since, two opposite sides of any parallelogram are always equal
Let's assume first side =a
second side =b
so, we get
[tex]a=2\sqrt[3]{54}x^2[/tex]
[tex]b=3\sqrt[3]{54}x^2[/tex]
now, we can find perimeter
perimeter=2a+2b
so, we get
[tex]p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)[/tex]
we can simplify it
[tex]p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2[/tex]
[tex]p=10\sqrt[3]{54}x^2[/tex]................Answer
The perimeter of the parallelogram whose base measure is [tex]2\sqrt[3]{{54}}{x^2}{\text{ cm}}[/tex] and whose oblique side is [tex]3\sqrt[3]{{54}}{x^2}{\text{ cm}}[/tex] is [tex]\boxed{10\sqrt[3]{{54}}{x^2}{\text{ cm}}}.[/tex]
Further explanation:
The perimeter of the parallelogram can be expressed as follows,
[tex]\boxed{{\text{Perimeter}} = 2 \times \left( {x + y} \right)}[/tex]
Given:
The base measure of the parallelogram is [tex]2\sqrt[3]{{54}}{x^2}{\text{ cm}}.[/tex]
The oblique measure of the parallelogram is [tex]3\sqrt[3]{{54}}{x^2}{\text{ cm}}.[/tex]
Explanation:
Consider the base measure of the parallelogram be “x”.
Consider the oblique side of the parallelogram as “y”.
The value of [tex]x = 2\sqrt[3]{{54}}{x^2}{\text{ cm}}.[/tex]
The value of [tex]y = 3\sqrt[3]{{54}}{x^2}{\text{ cm}}.[/tex]
The perimeter of the parallelogram can be obtained as follows,
[tex]\begin{aligned}{\text{Perimeter}} &= 2x + 2y\\&= 2\left( {x + y} \right)\\&= 2\left( {2\sqrt[3]{{54}} + 3\sqrt[3]{{54}}} \right)\\&= 2\left( {5\sqrt[3]{{54}}} \right)\\&= 10\sqrt[3]{{54}}\\\end{aligned}[/tex]
The perimeter of the parallelogram whose base measure is [tex]2\sqrt[3]{{54}}{x^2}{\text{ cm}}[/tex] and whose oblique side is [tex]3\sqrt[3]{{54}}{x^2}{\text{ cm}} \:{\text{is} \:\boxed{10\sqrt[3]{{54}}{x^2}{\text{ cm}}}.[/tex]
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Answer details:
Grade: High School
Subject: Mathematics
Chapter:
Keywords: Area, perimeter, total, parallelogram, base measure, oblique side measure, total perimeter.
