Respuesta :
Answer : The structure of [tex]XeH_4[/tex] will be square-planar.
Explanation :
In the given molecule [tex]XeH_4[/tex], 'Xe' is the central atom and 'H' is the terminal atom.
Xenon has 8 valence electrons and hydrogen has 1 valence electron. Therefore, the total number of valence electrons are 8 + 4(1) = 12 electrons.
The number of electrons used in Xe-H bonding = 8 electrons
The remaining electrons which are used as lone pair on central atom (Xe) = 12 - 8 = 4 electrons
There are 4 bonding pairs and 2 lone pairs of electrons, they will be arranged in the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. The resulting structure will be square-planar.
The structure of [tex]XeH_4[/tex] is shown below.
The structure of Xenon -Hydrogen will be square planar.
The molecule of Xe has 8 valence electons. The molecule of H has 1 valence electron.
The 4 hydrogen will form bonds with the 4 valence electrons of Xe. There will be 8 bonding electrons.
The remaining 4 electrons of Xe will be the loan pair that effect the shape of the structure.
The arrangement of 4 bonding pairs and 2 lone pairs of electrons, will be the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. They will distort the geometry of the structure. The resulting structure will be square-planar.
For more information about the structure, refer the link:
https://brainly.com/question/9055331?referrer=searchResults
