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The equilibrium constant for the reaction of hydrogen gas and oxygen gas to produce water at 500 k is 2.4 × 1047. what does the magnitude of the equilibrium constant tell us about the reaction? 2 h2(g) + o2(g) ⇄ 2 h2o(g) k = 2.4 × 1047

Respuesta :

Given reaction:

2H2(g) + O2(g) ↔ 2H2O (g)

The equilibrium constant can be expressed as

1) a ratio of the concentration of products to that of the reactants

Keq = [H2O]²/[H2]²[O2] = 2.4 * 10⁴⁷

2) It can also be expressed as a ratio of the rate of forward reaction to that of the reverse

Keq = k(forward)/k(reverse)

Since the Keq value is quite high, this implies that k(f) >> k(r). i.e. the rate of formation of product (water) is much higher than the reactant


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