Sound Level of 50 dB is given to us
So the intensity of sound for this level of sound is given as
[tex]L = 10 Log \frac{I}{I_0}[/tex]
now we will have
[tex]L = 50 dB[/tex]
[tex]50 = 10 Log\frac{I}{1 \times 10^{-12}}[/tex]
by solving above equation we will have
[tex]I = 10^{-7} W/m^2[/tex]
now energy received by ear drum per second will be
[tex]P = intensity \times area[/tex]
[tex]P = 10^{-7} \times 5 \times 10^{-5} = 5 \times 10^{-12} W[/tex]
Now total energy received in one year will be
[tex]E = power \times time[/tex]
[tex]E = 5 \times 10^{-12} \times 3.156 \times 10^7[/tex]
[tex]E = 1.6 \times 10^{-4} J[/tex]
so above is the energy received by year in one year
