Respuesta :
Answer:- Pressure of the gas is 790.4 mmHg.
Solution:- Mass of the gas oxygen gas is 4.00 g, temperature is 30.0 degree C and volume is 3000 mL and it asks to calculate the pressure of the gas.
It is based on ideal gas law equation, PV = nRT
Where, P is pressure, V is volume, n is number of moles, R is the universal gas constant and T is temperature.
Let's convert the mass to moles on dividing the grams by molar mass. Molar mass of oxygen is 32 gram per mol.
n = [tex]4.00g(\frac{1mol}{32g})[/tex]
n = 0.125 moles
Convert degree C to kelvin, for this we add 273.
T = 30.0 + 273 = 303 K
Convert mL to L. For this we divide the given volume by 1000.
V = [tex]3000mL(\frac{1L}{1000mL})[/tex]
V = 3 L
Value of R is 0.0821 atm.L per mol per K.
The equation is rearranged for the pressure as:
[tex]P=\frac{nRT}{V}[/tex]
Let's plug in the values in the equation to calculate the pressure, P.
[tex]P=\frac{0.125*0.0821*303}{3}[/tex]
P = 1.04 atm
They want answer in mmHg, so let's convert the pressure unit from atm to mmHg.
1 atm = 760 mmHg
so, [tex]1.04atm(\frac{760mmHg}{1atm})[/tex]
= 790.4 mmHg
So, the pressure of the gas is 790.4 mmHg.
