What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrogen to form solid molybdenum and liquid water?

Respuesta :

The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


 Explanation

Coefficient   is defined  to  as  a number  in front   of a chemical formula in a  balanced chemical equation.

   The  reaction   of   molybdenum (iv) oxide  with  gaseous  hydrogen  is  as below,


MoO2  + 2 H2→  Mo  +2 H2O

From   balanced equation above  the coefficient   for  H2  is  2  since  the number in  front of  H2  is 2



The coefficient is the constant number that is placed before the balanced chemical of the reaction. The coefficient of hydrogen in the reaction is 2.

What is a Coefficient?

A Coefficient is a specific number that is written before the balanced atom of a reaction.  They are used to write the balanced chemical reactions.

The reaction of solid molybdenum (iv) oxide with gaseous hydrogen can be shown as:

[tex]\rm MoO_{2} + 2 H_{2} \rightarrow Mo +2 H_{2}O[/tex]

Hydrogen reacts with molybdenum (iv) oxide to form solid molybdenum and liquid water.

From the balanced chemical reaction, it can be seen that 2 is the coefficient of the hydrogen atom.

Therefore, 2 is the coefficient of hydrogen.

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