A school basketball team has an expense account and a fundraising account. After tt weeks, the balance of the expense account is (400βˆ’40t)(400βˆ’40t) dollars and the balance of the fundraising account is (150+32t)(150+32t) dollars.


a. Write an expression in simplest form that represents the total amount (in dollars) in both accounts after tt weeks.

An expression is (

550βˆ’72t) dollars.


b. What is the total amount (in dollars) in both accounts after 12 weeks?


Amount after 12 weeks: $

Respuesta :

Answer:

a. 550-8t

b. 454 dollars

Step-by-step explanation:


a. Calling t the number of weeks, the balance in the first account is

[tex](400-40t)[/tex]

while the balance in the second account is

[tex](150+32t)[/tex]

So, the total amount in both accounts is the sum of the balances of the two accounts:

[tex](400-40t)+(150+32t)=(400+150)+(-40t+32t)=550-8t[/tex]


b. To find the total amount in both accounts after 12 weeks, we just need to substitute t=12 into the total balance, and we find:

[tex]550-8t=550-8\cdot 12=550-96=454[/tex]

Answer:

a. 550-8t

b. 454 dollars

Step-by-step explanation:

a. Calling t the number of weeks, the balance in the first account is

(400-40t)(400βˆ’40t)

while the balance in the second account is

(150+32t)(150+32t)

So, the total amount in both accounts is the sum of the balances of the two accounts:

(400-40t)+(150+32t)=(400+150)+(-40t+32t)=550-8t(400βˆ’40t)+(150+32t)=(400+150)+(βˆ’40t+32t)=550βˆ’8t

b. To find the total amount in both accounts after 12 weeks, we just need to substitute t=12 into the total balance, and we find:

550-8t=550-8\cdot 12=550-96=454550βˆ’8t=550βˆ’8β‹…12=550βˆ’96=454