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The angle of depression from the top of a cliff 50 metres above sea level to a ship sailing off the cliff is 22 degrees. How far is the yacht from the base of the cliff?

Respuesta :

deboada35

1) First step e

be x the distance of the ship till to cliff,  as you can observe the figure and applying   tangent in a triangle rectangle

tg α= CO / X⇒X = CO/tgα ⇒ X = 50/ tg 22° ⇒x = 123,75 the distance of the yacht  till the base of the cliff is 123,75 m

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