How do I find the value of 16 to the -3/2 power?

Hello!
Explanation:
First, used exponent rules.
[tex]a^-^b=\frac{1}{a^b}[/tex]
[tex]\frac{1}{16^3^/^2}=64[/tex]
Then factor by the numbers.
[tex]4^2=16=4^2[/tex]
[tex](4^2)\frac{3}{2}[/tex]
[tex]4^3[/tex]
Refine.
[tex]4^3=4*4*4=64[/tex]
[tex]=\frac{1}{64}[/tex]
Answer: → [tex]\frac{1}{64}[/tex]
Hope this helps!
Thanks!
-Charlie