A layer of oil 1.50 mm thick is placed between two microscope slides. researchers find that a force of 5.50Ã10â4 n is required to glide one over the other at a speed of 1.00 cm/s when their contact area is 6.00 cm2. what is the oil's viscosity? what type of oil might it be?

Respuesta :

Force to slide the two surface over each other is given as

[tex]F = \eta A \frac{dv}{dx}[/tex]

as we know that

[tex]F = 5.50 \times 10^{-4} N[/tex]

[tex]A = 6 \times 10^{-4}[/tex]

[tex]\frac{dv}{dx} = \frac{1\times 10^{-2}}{1.50 \times 10^{-3}}[/tex]

now plug in all data in above formula

[tex]5.50 \times 10^{-4} = \eta 6 \times 10^{-4} \frac{1 \times 10^{-4}}{1.50 \times 10^{-3}}[/tex]

[tex]\eta = 0.1375 Pa s[/tex]

This is approximate range of Motor Oil