The mass of solid formed is 2.654 g
calculation
step 1: write the balanced molecular equation
=2AgNO3(aq) + k2CrO4(aq)→ Ag2CrO4(s) + 2 KNO3(aq)
step 2: calculate the moles of K2CrO4
moles = molarity x volume in liters
molarity = 0.200 M = 0.200 mol/L
volume = 40 .0 ml in liters = 40/1000 = 0.04 liters
moles is = 0.200 mol/l x0.04 L =0.008 moles
Step 3: use the mole ratio to determine the moles of solid formed( Ag2CrO4)
K2CrO4 :Ag2CrO4 is 1:1 therefore the moles of Ag2CrO4 is also
0.008 moles
step 4: calculate the mass of Ag2CrO4
mass = moles x molar mass
from periodic table the molar mass of Ag2Cro4
=(107.87 x2) + 52 +(16 x4) =331.74 g/mol
mass = 0.008 moles x 331.74 = 2.654 g
